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Application of Integrals – Area of Circle & Ellipse

Using definite integrals to derive area formulas for standard curves (circle and ellipse).
Idea: integrate the upper half of the curve and double it, using symmetry about the x-axis.

1. Area of a Circle using Integrals

Equation of the circle

Circle of radius \(r\):\quad \(x^2 + y^2 = r^2\)
Upper semicircle: \(\;y = \sqrt{r^2 - x^2}\)

Area by integration

\[ A = 2\int_{-r}^{r} \sqrt{r^2 - x^2}\,dx \] Use substitution \(x = r\sin\theta\). After simplification, \[ A = \pi r^2 \]

2. Area of an Ellipse using Integrals

Equation of the ellipse

Standard ellipse with semi-axes \(a\) (x-direction) and \(b\) (y-direction):
\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Upper half: \[ y = b\sqrt{1 - \frac{x^2}{a^2}} \]

Area by integration

\[ A = 2\int_{-a}^{a} b\sqrt{1 - \frac{x^2}{a^2}}\,dx \] Substitute \(x = a\sin\theta\). Then \(dx = a\cos\theta\,d\theta\), and limits change from \(-a \to -\frac{\pi}{2}\) to \(+a \to \frac{\pi}{2}\). \[ A = 2b\int_{-\pi/2}^{\pi/2} b\sqrt{1-\sin^2\theta}\,a\cos\theta\,d\theta = 2ab\int_{-\pi/2}^{\pi/2} \cos^2\theta\,d\theta = \pi ab \]

3. Comparison – Circle vs Ellipse

Shape Equation Integral Expression Final Area
Circle \(x^2 + y^2 = r^2\) \(2\displaystyle\int_{-r}^{r} \sqrt{r^2 - x^2}\,dx\) \(\pi r^2\)
Ellipse \(\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1\) \(2\displaystyle\int_{-a}^{a} b\sqrt{1 - x^2/a^2}\,dx\) \(\pi ab\)
Note: A circle is a special ellipse with \(a = b = r\). Then \(\pi ab \Rightarrow \pi r^2\).

4. Quick Concept Insight

Application of Integrals Area under Curves Circle & Ellipse